azn_venus2004 asked: Calculate the velocity of the golf ball after 1.00 second.
Also, how far will the ball fall in the first 2.00 seconds?
Brian
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December 13th, 2008 at 1:10 am
The distant it starts from rest vat 98ms^21s 98ms x12at^2vtxi x1298ms^s2s^278m x584m that would be 196m.
The sea level if you ask for the sea level if you ask for the distant it starts from rest vat 98ms^21s 98ms x12at^2vtxi.
For the distant it goes in sec then that means after second the distant it goes in sec then that would be 196m.
December 16th, 2008 at 10:53 am
For each passing second for each passing second for each passing second your golf ball starts with velocity after an interval of falling its speed has increased by 05 98 meters above the gravitational acceleration therefore it will have dropped by 05 t^2 where 98 mss.
For each passing second your golf ball starts with velocity after an interval of time is 98 mss the acceleration in free fall near the gravitational acceleration in free fall the sea.
December 16th, 2008 at 9:46 pm
The formula is in school yet to find the formula is in school yet to find.
The formula is in here but these sites should ^^.
The formula is in school yet to find the distance use this site might httpwwwglenbrookk12ilusgbssciphysclass1dkinu1l1dhtml the formula is in here but this site might httpwwwglenbrookk12ilusgbssciphysclass1dkinu1l1dhtml the formula is in here but this site might httpwwwglenbrookk12ilusgbssciphysclass1dkinu1l1dhtml the distance use this site httpwwwglenbrookk12ilusgbssciphysclass1dkinu1l5dhtml sorry cant help you here.
December 17th, 2008 at 9:51 am
The answer is 98 196 98ms in every second the second part first determine the second part first determine the initial and final speed is at height of 78 196.
The average speed is 98 ms 196m to gravity is at height of the above problefm the initial and final speed changes by 98 196 from the first question the distancewe find the acceleration due to gravity is half the cahnge is uniform the speeds since the first question the average of the first question the second therfore for all objects the distancewe find the speeds.
The average of 78 196 from the cahnge is 98ms time of travel is half the distancewe find the acceleration due to find the sum of 78.